integral from-1 to 2 of x^3+8

Lösung

\int_{- 1}^{2} x^{3} + 8 d x

\frac{111}{4}

Dezimale

27.75

Schritte zur Lösung

\int_{- 1}^{2} x^{3} + 8 d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{- 1}^{2} x^{3} d x + \int_{- 1}^{2} 8 d x

\int_{- 1}^{2} x^{3} d x = \frac{15}{4}

\int_{- 1}^{2} 8 d x = 24

= \frac{15}{4} + 24

Vereinfache

\frac{15}{4} + 24 : \frac{111}{4}

= \frac{111}{4}

\int_{- π}^{π} ∣ t ∣ d t

\int_{0}^{y} x^{2} + y^{2} d x

\int_{0}^{x} 4 + t^{6} d x

\int_{0}^{1} 1 + 8 t^{2} d t

\int_{0}^{1} π (y - y^{2})^{2} d y