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Popular Calculus >

integral from-1 to 1 of (3-x^2)

Solution

\int_{- 1}^{1} (3 - x^{2}) d x

Solution

\frac{16}{3}

+1

Decimal

5.33333 \dots

Solution steps

\int_{- 1}^{1} 3 - x^{2} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{- 1}^{1} 3 d x - \int_{- 1}^{1} x^{2} d x

\int_{- 1}^{1} 3 d x = 6

\int_{- 1}^{1} x^{2} d x = \frac{2}{3}

= 6 - \frac{2}{3}

Simplify

6 - \frac{2}{3} : \frac{16}{3}

= \frac{16}{3}

Graph

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Frequently Asked Questions (FAQ)

What is the integral from-1 to 1 of (3-x^2) ?
The integral from-1 to 1 of (3-x^2) is 16/3