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Popular Calculus >

integral from-2 to 1 of (2x^2+8)

Solution

\int_{- 2}^{1} (2 x^{2} + 8) d x

Solution

30

Solution steps

\int_{- 2}^{1} 2 x^{2} + 8 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{- 2}^{1} 2 x^{2} d x + \int_{- 2}^{1} 8 d x

\int_{- 2}^{1} 2 x^{2} d x = 6

\int_{- 2}^{1} 8 d x = 24

= 6 + 24

Simplify

= 30

Graph

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Frequently Asked Questions (FAQ)

What is the integral from-2 to 1 of (2x^2+8) ?
The integral from-2 to 1 of (2x^2+8) is 30