What is the integral from 1 to 4 of 1/((x-2)^2) ?

The integral from 1 to 4 of 1/((x-2)^2) is diverges

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

integral from 1 to 4 of 1/((x-2)^2)

\int_{1}^{4} \frac{1}{( x - 2 ) ^{2}} d x

diverges

Solution steps

\int_{1}^{4} \frac{1}{( x - 2 ) ^{2}} d x

Find undefined (singularity) points:

x = 2

If exist

b, a < b < c, f (b) =

undefined

, \int_{a}^{c} f (x) d x = \int_{a}^{b} f (x) d x + \int_{b}^{c} f (x) d x

= \int_{1}^{2} \frac{1}{( x - 2 ) ^{2}} d x + \int_{2}^{4} \frac{1}{( x - 2 ) ^{2}} d x

\int_{1}^{2} \frac{1}{( x - 2 ) ^{2}} d x =

diverges

If part of the expression diverges, then entire expression diverges

= diverges

What is the integral from 1 to 4 of 1/((x-2)^2) ?
The integral from 1 to 4 of 1/((x-2)^2) is diverges