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Popular Calculus >

integral from-1 to 1 of (y-1)

Solution

\int_{- 1}^{1} (y - 1) d y

Solution

- 2

Solution steps

\int_{- 1}^{1} y - 1 d y

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{- 1}^{1} y d y - \int_{- 1}^{1} 1 d y

\int_{- 1}^{1} y d y = 0

\int_{- 1}^{1} 1 d y = 2

= 0 - 2

Simplify

= - 2

Graph

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Frequently Asked Questions (FAQ)

What is the integral from-1 to 1 of (y-1) ?
The integral from-1 to 1 of (y-1) is -2