What is the integral from-1 to 0 of (2x+1)^3 ?

The integral from-1 to 0 of (2x+1)^3 is 0

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

integral from-1 to 0 of (2x+1)^3

\int_{- 1}^{0} (2 x + 1)^{3} d x

0

Solution steps

\int_{- 1}^{0} (2 x + 1)^{3} d x

Apply u-substitution

= \int_{- 1}^{1} \frac{u ^{3}}{2} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{2} \cdot \int_{- 1}^{1} u^{3} d u

Apply the Power Rule

= \frac{1}{2} [\frac{u ^{4}}{4}]_{- 1}^{1}

Compute the boundaries:

0

= \frac{1}{2} \cdot 0

Simplify

= 0

What is the integral from-1 to 0 of (2x+1)^3 ?
The integral from-1 to 0 of (2x+1)^3 is 0