What is the integral from 1 to 6 of (ln(x))/x ?

The integral from 1 to 6 of (ln(x))/x is (ln^2(6))/2

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integral from 1 to 6 of (ln(x))/x

\int_{1}^{6} \frac{ln ( x )}{x} d x

\frac{ln ^{2} ( 6 )}{2}

Decimal

1.60520 \dots

Solution steps

\int_{1}^{6} \frac{ln ( x )}{x} d x

Apply u-substitution

= \int_{0}^{l n (6)} u d u

Apply the Power Rule

= [\frac{u ^{2}}{2}]_{0}^{l n (6)}

Compute the boundaries:

\frac{ln ^{2} ( 6 )}{2}

= \frac{ln ^{2} ( 6 )}{2}

What is the integral from 1 to 6 of (ln(x))/x ?
The integral from 1 to 6 of (ln(x))/x is (ln^2(6))/2