What is the integral from 1 to infinity of 1/(8x+4) ?

The integral from 1 to infinity of 1/(8x+4) is diverges

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integral from 1 to infinity of 1/(8x+4)

\int_{1}^{\infty} \frac{1}{8 x + 4} d x

diverges

Solution steps

\int_{1}^{\infty} \frac{1}{8 x + 4} d x

Compute the indefinite integral:

\int \frac{1}{8 x + 4} d x = \frac{1}{8} ln ∣ 8 x + 4 ∣ + C

Compute the boundaries:

\int_{1}^{\infty} \frac{1}{8 x + 4} d x =

diverges

= diverges

What is the integral from 1 to infinity of 1/(8x+4) ?
The integral from 1 to infinity of 1/(8x+4) is diverges