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Popular Calculus >

integral from-1 to 0 of |4x+3|

Solution

\int_{- 1}^{0} ∣ 4 x + 3 ∣ d x

Solution

\frac{5}{4}

+1

Decimal

1.25

Solution steps

\int_{- 1}^{0} ∣ 4 x + 3 ∣ d x

Eliminate Absolutes

= \int_{- 1}^{- \frac{3}{4}} - 4 x - 3 d x + \int_{- \frac{3}{4}}^{0} 4 x + 3 d x

\int_{- 1}^{- \frac{3}{4}} - 4 x - 3 d x = \frac{1}{8}

\int_{- \frac{3}{4}}^{0} 4 x + 3 d x = \frac{9}{8}

= \frac{1}{8} + \frac{9}{8}

Simplify

\frac{1}{8} + \frac{9}{8} : \frac{5}{4}

= \frac{5}{4}

Graph

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Frequently Asked Questions (FAQ)

What is the integral from-1 to 0 of |4x+3| ?
The integral from-1 to 0 of |4x+3| is 5/4