What is the integral from 0 to 1 of 1/y+sqrt(x) ?

The integral from 0 to 1 of 1/y+sqrt(x) is 1/y+2/3

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integral from 0 to 1 of 1/y+sqrt(x)

\int_{0}^{1} \frac{1}{y} + x d x

\frac{1}{y} + \frac{2}{3}

Solution steps

\int_{0}^{1} \frac{1}{y} + x d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{1} \frac{1}{y} d x + \int_{0}^{1} x d x

\int_{0}^{1} \frac{1}{y} d x = \frac{1}{y}

\int_{0}^{1} x d x = \frac{2}{3}

= \frac{1}{y} + \frac{2}{3}

What is the integral from 0 to 1 of 1/y+sqrt(x) ?
The integral from 0 to 1 of 1/y+sqrt(x) is 1/y+2/3