What is the integral from 0 to 6 of x/(18) ?

The integral from 0 to 6 of x/(18) is 1

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integral from 0 to 6 of x/(18)

\int_{0}^{6} \frac{x}{18} d x

1

Solution steps

\int_{0}^{6} \frac{x}{18} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{18} \cdot \int_{0}^{6} x d x

Apply the Power Rule

= \frac{1}{18} [\frac{x ^{2}}{2}]_{0}^{6}

Compute the boundaries:

18

= \frac{1}{18} \cdot 18

Simplify

= 1

What is the integral from 0 to 6 of x/(18) ?
The integral from 0 to 6 of x/(18) is 1