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Popular Calculus >

integral from 0 to 4 of |3x-9|

Solution

\int_{0}^{4} ∣ 3 x - 9 ∣ d x

Solution

15

Solution steps

\int_{0}^{4} ∣ 3 x - 9 ∣ d x

Eliminate Absolutes

= \int_{0}^{3} - 3 x + 9 d x + \int_{3}^{4} 3 x - 9 d x

\int_{0}^{3} - 3 x + 9 d x = \frac{27}{2}

\int_{3}^{4} 3 x - 9 d x = \frac{3}{2}

= \frac{27}{2} + \frac{3}{2}

Simplify

\frac{27}{2} + \frac{3}{2} : 15

= 15

Graph

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Frequently Asked Questions (FAQ)

What is the integral from 0 to 4 of |3x-9| ?
The integral from 0 to 4 of |3x-9| is 15