What is the integral from 0 to 180 of sin(x) ?

The integral from 0 to 180 of sin(x) is -cos(180)+1

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integral from 0 to 180 of sin(x)

\int_{0}^{180} sin (x) d x

- cos (180) + 1

Decimal

1.59846 \dots

Solution steps

\int_{0}^{180} sin (x) d x

Use the common integral:

\int sin (x) d x = - cos (x)

= [- cos (x)]_{0}^{180}

Compute the boundaries:

- cos (180) + 1

= - cos (180) + 1

What is the integral from 0 to 180 of sin(x) ?
The integral from 0 to 180 of sin(x) is -cos(180)+1