What is the integral from-2 to 5 of (x^2+6x+8) ?

The integral from-2 to 5 of (x^2+6x+8) is 490/3

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integral from-2 to 5 of (x^2+6x+8)

\int_{- 2}^{5} (x^{2} + 6 x + 8) d x

\frac{490}{3}

Decimal

163.33333 \dots

Solution steps

\int_{- 2}^{5} x^{2} + 6 x + 8 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{- 2}^{5} x^{2} d x + \int_{- 2}^{5} 6 x d x + \int_{- 2}^{5} 8 d x

\int_{- 2}^{5} x^{2} d x = \frac{133}{3}

\int_{- 2}^{5} 6 x d x = 63

\int_{- 2}^{5} 8 d x = 56

= \frac{133}{3} + 63 + 56

Simplify

\frac{133}{3} + 63 + 56 : \frac{490}{3}

= \frac{490}{3}

What is the integral from-2 to 5 of (x^2+6x+8) ?
The integral from-2 to 5 of (x^2+6x+8) is 490/3