en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular Calculus >

integral from 0 to 4 of (-2x+2)

Solution

\int_{0}^{4} (- 2 x + 2) d x

Solution

- 8

Solution steps

\int_{0}^{4} - 2 x + 2 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= - \int_{0}^{4} 2 x d x + \int_{0}^{4} 2 d x

\int_{0}^{4} 2 x d x = 16

\int_{0}^{4} 2 d x = 8

= - 16 + 8

Simplify

= - 8

Graph

Popular Examples

integral from e^{-t} to e^{t-1 of}ln(x)

integral from-pi to pi of cos(x)cos(3x)

integral from 0 to 3 of x/(2+x^2)

integral from e^{-t} to e^{1-t of}ln(x)

integral from 1 to e^2 of ln(2x)

Frequently Asked Questions (FAQ)

What is the integral from 0 to 4 of (-2x+2) ?
The integral from 0 to 4 of (-2x+2) is -8