What is the integral from 1 to 2 of (3x^2+4x-2) ?

The integral from 1 to 2 of (3x^2+4x-2) is 11

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integral from 1 to 2 of (3x^2+4x-2)

\int_{1}^{2} (3 x^{2} + 4 x - 2) d x

11

Solution steps

\int_{1}^{2} 3 x^{2} + 4 x - 2 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{1}^{2} 3 x^{2} d x + \int_{1}^{2} 4 x d x - \int_{1}^{2} 2 d x

\int_{1}^{2} 3 x^{2} d x = 7

\int_{1}^{2} 4 x d x = 6

\int_{1}^{2} 2 d x = 2

= 7 + 6 - 2

Simplify

= 11

What is the integral from 1 to 2 of (3x^2+4x-2) ?
The integral from 1 to 2 of (3x^2+4x-2) is 11