What is the integral from 1 to 2 of sin(sqrt(x-1)) ?

The integral from 1 to 2 of sin(sqrt(x-1)) is 2(sin(1)-cos(1))

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integral from 1 to 2 of sin(sqrt(x-1))

\int_{1}^{2} sin (x - 1) d x

2 (sin (1) - cos (1))

Decimal

0.60233 \dots

Solution steps

\int_{1}^{2} sin (x - 1) d x

Apply u-substitution

= \int_{0}^{1} sin (u) \cdot 2 u d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 2 \cdot \int_{0}^{1} sin (u) u d u

Apply Integration By Parts

= 2 [- u cos (u) - \int - cos (u) d u]_{0}^{1}

\int - cos (u) d u = - sin (u)

= 2 [- u cos (u) - (- sin (u))]_{0}^{1}

Simplify

= 2 [- u cos (u) + sin (u)]_{0}^{1}

Compute the boundaries:

sin (1) - cos (1)

= 2 (sin (1) - cos (1))

What is the integral from 1 to 2 of sin(sqrt(x-1)) ?
The integral from 1 to 2 of sin(sqrt(x-1)) is 2(sin(1)-cos(1))