What is the integral from 100 to 150 of-0.006x^2+20x ?

The integral from 100 to 150 of-0.006x^2+20x is 120250

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integral from 100 to 150 of-0.006x^2+20x

\int_{100}^{150} - 0.006 x^{2} + 20 x d x

120250

Solution steps

\int_{100}^{150} - 0.006 x^{2} + 20 x d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= - \int_{100}^{150} 0.006 x^{2} d x + \int_{100}^{150} 20 x d x

\int_{100}^{150} 0.006 x^{2} d x = 4750

\int_{100}^{150} 20 x d x = 125000

= - 4750 + 125000

Simplify

= 120250

What is the integral from 100 to 150 of-0.006x^2+20x ?
The integral from 100 to 150 of-0.006x^2+20x is 120250