derivative f(x)=x^3-6x^2+9x

Lösung

ableitung von

f (x) = x^{3} - 6 x^{2} + 9 x

3 x^{2} - 12 x + 9

Schritte zur Lösung

\frac{d}{d x} (x^{3} - 6 x^{2} + 9 x)

Wende die Summen-/Differenzregel an:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{3}) - \frac{d}{d x} (6 x^{2}) + \frac{d}{d x} (9 x)

\frac{d}{d x} (x^{3}) = 3 x^{2}

\frac{d}{d x} (6 x^{2}) = 12 x

\frac{d}{d x} (9 x) = 9

= 3 x^{2} - 12 x + 9

x \to \frac{π}{4} lim (tan (2 x))

\int \frac{7 x + 3}{x} d x

x \to \infty lim (x^{4})

l a pl a ce t r an s f or m cos (k t)

a re a y = 3 x, y = \frac{1}{x}, x = 8, x = 1