What is the integral of 3/(x^4) 1 ?

The integral of 3/(x^4) 1 is -d/(x^3)+C

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integral of 3/(x^4) 1

\int \frac{3}{x ^{4}} \frac{d}{1} d x

- \frac{d}{x ^{3}} + C

Solution steps

\int \frac{3}{x ^{4}} \cdot \frac{d}{1} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 3 d \cdot \int \frac{1}{x ^{4}} d x

Apply the Power Rule

= 3 d (- \frac{1}{3 x ^{3}})

Simplify

3 d (- \frac{1}{3 x ^{3}}) : - \frac{d}{x ^{3}}

= - \frac{d}{x ^{3}}

Add a constant to the solution

= - \frac{d}{x ^{3}} + C