What is the integral of 2/x-2/(x^2) ?

The integral of 2/x-2/(x^2) is 2ln|x|+2/x+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

integral of 2/x-2/(x^2)

\int \frac{2}{x} - \frac{2}{x ^{2}} d x

2 ln ∣ x ∣ + \frac{2}{x} + C

Solution steps

\int \frac{2}{x} - \frac{2}{x ^{2}} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int \frac{2}{x} d x - \int \frac{2}{x ^{2}} d x

\int \frac{2}{x} d x = 2 ln ∣ x ∣

\int \frac{2}{x ^{2}} d x = - \frac{2}{x}

= 2 ln ∣ x ∣ - (- \frac{2}{x})

Simplify

= 2 ln ∣ x ∣ + \frac{2}{x}

Add a constant to the solution

= 2 ln ∣ x ∣ + \frac{2}{x} + C

What is the integral of 2/x-2/(x^2) ?
The integral of 2/x-2/(x^2) is 2ln|x|+2/x+C