What is the integral of (x+4)^{-2} ?

The integral of (x+4)^{-2} is -1/(x+4)+C

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integral of (x+4)^{-2}

\int (x + 4)^{- 2} d x

- \frac{1}{x + 4} + C

Solution steps

\int (x + 4)^{- 2} d x

Apply u-substitution

= \int \frac{1}{u ^{2}} d u

Apply the Power Rule

= - \frac{1}{u}

Substitute back

u = x + 4

= - \frac{1}{x + 4}

Add a constant to the solution

= - \frac{1}{x + 4} + C