What is the integral of 2picos(nx) ?

The integral of 2picos(nx) is (2pi)/n sin(nx)+C

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integral of 2picos(nx)

\int 2 π cos (n x) d x

\frac{2 π}{n} sin (n x) + C

Solution steps

\int 2 π cos (n x) d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 2 π \cdot \int cos (n x) d x

Apply u-substitution

= 2 π \cdot \int \frac{cos ( u )}{n} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 2 π \frac{1}{n} \cdot \int cos (u) d u

Use the common integral:

\int cos (u) d u = sin (u)

= 2 π \frac{1}{n} sin (u)

Substitute back

u = n x

= 2 π \frac{1}{n} sin (n x)

Simplify

2 π \frac{1}{n} sin (n x) : \frac{2 π}{n} sin (n x)

= \frac{2 π}{n} sin (n x)

Add a constant to the solution

= \frac{2 π}{n} sin (n x) + C

What is the integral of 2picos(nx) ?
The integral of 2picos(nx) is (2pi)/n sin(nx)+C