2ty^'-3y=0

Lösung

2 t y^{^{'}} - 3 y = 0

y = c_{1} t^{\frac{3}{2}}

Schritte zur Lösung

2 t y^{'} (t) - 3 y = 0

Solve separable ODE:

y = c_{1} t^{\frac{3}{2}}

y = c_{1} t^{\frac{3}{2}}

t an g e n t f (x) = \frac{7}{x ^{4}}, at x = - 3

t an g e n t y = x + 2, (- 1, 1)

\frac{d y}{d x} = \frac{y ^{2} + x y + x ^{2}}{x ^{2}}, y (1) = - 1

x \to - 4 + lim (\frac{- 2}{x ^{2} - 16})

\int \frac{32 x ^{2}}{( x - 12 ) ( x + 4 ) ^{2}} d x