What is the integral of (1-2x^2)/x ?

The integral of (1-2x^2)/x is ln|x|-x^2+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

integral of (1-2x^2)/x

\int \frac{1 - 2 x ^{2}}{x} d x

ln ∣ x ∣ - x^{2} + C

Solution steps

\int \frac{1 - 2 x ^{2}}{x} d x

Expand

\frac{1 - 2 x ^{2}}{x} : \frac{1}{x} - 2 x

= \int \frac{1}{x} - 2 x d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int \frac{1}{x} d x - \int 2 x d x

\int \frac{1}{x} d x = ln ∣ x ∣

\int 2 x d x = x^{2}

= ln ∣ x ∣ - x^{2}

Add a constant to the solution

= ln ∣ x ∣ - x^{2} + C