derivative-0.1x^2+0.8x+9

Lösung

ableitung von

- 0.1 x^{2} + 0.8 x + 9

- 0.2 x + 0.8

Schritte zur Lösung

\frac{d}{d x} (- 0.1 x^{2} + 0.8 x + 9)

Wende die Summen-/Differenzregel an:

(f \pm g)^{'} = f^{'} \pm g^{'}

= - \frac{d}{d x} (0.1 x^{2}) + \frac{d}{d x} (0.8 x) + \frac{d}{d x} (9)

\frac{d}{d x} (0.1 x^{2}) = 0.2 x

\frac{d}{d x} (0.8 x) = 0.8

\frac{d}{d x} (9) = 0

= - 0.2 x + 0.8 + 0

Vereinfache

= - 0.2 x + 0.8

\int \frac{e ^{a r c t a n (x)}}{x ^{2} + 1} d x

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t an g e n t f (x) = x^{2} - 4, (5, 21)

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