What is the integral of (5x+16)^4 ?

The integral of (5x+16)^4 is 1/25 (5x+16)^5+C

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integral of (5x+16)^4

\int (5 x + 16)^{4} d x

\frac{1}{25} (5 x + 16)^{5} + C

Solution steps

\int (5 x + 16)^{4} d x

Apply u-substitution

= \int \frac{u ^{4}}{5} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{5} \cdot \int u^{4} d u

Apply the Power Rule

= \frac{1}{5} \cdot \frac{u ^{5}}{5}

Substitute back

u = 5 x + 16

= \frac{1}{5} \cdot \frac{( 5 x + 16 ) ^{5}}{5}

Simplify

\frac{1}{5} \cdot \frac{( 5 x + 16 ) ^{5}}{5} : \frac{1}{25} (5 x + 16)^{5}

= \frac{1}{25} (5 x + 16)^{5}

Add a constant to the solution

= \frac{1}{25} (5 x + 16)^{5} + C

What is the integral of (5x+16)^4 ?
The integral of (5x+16)^4 is 1/25 (5x+16)^5+C