What is the integral of 3600-120x ?

The integral of 3600-120x is 3600x-60x^2+C

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integral of 3600-120x

\int 3600 - 120 x d x

3600 x - 60 x^{2} + C

Solution steps

\int 3600 - 120 x d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int 3600 d x - \int 120 x d x

\int 3600 d x = 3600 x

\int 120 x d x = 60 x^{2}

= 3600 x - 60 x^{2}

Add a constant to the solution

= 3600 x - 60 x^{2} + C