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Popular Calculus >

integral of (4^x+2)

Solution

\int (4^{x} + 2) d x

Solution

\frac{2 ^{2 x - 1}}{ln ( 2 )} + 2 x + C

Solution steps

\int 4^{x} + 2 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int 4^{x} d x + \int 2 d x

\int 4^{x} d x = \frac{2 ^{2 x - 1}}{ln ( 2 )}

\int 2 d x = 2 x

= \frac{2 ^{2 x - 1}}{ln ( 2 )} + 2 x

Add a constant to the solution

= \frac{2 ^{2 x - 1}}{ln ( 2 )} + 2 x + C

Graph

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Frequently Asked Questions (FAQ)

What is the integral of (4^x+2) ?
The integral of (4^x+2) is (2^{2x-1})/(ln(2))+2x+C