What is the integral of 3t^2(t^3+2)^{3/2} ?

The integral of 3t^2(t^3+2)^{3/2} is 2/5 (t^3+2)^{5/2}+C

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integral of 3t^2(t^3+2)^{3/2}

\int 3 t^{2} (t^{3} + 2)^{\frac{3}{2}} d t

\frac{2}{5} (t^{3} + 2)^{\frac{5}{2}} + C

Solution steps

\int 3 t^{2} (t^{3} + 2)^{\frac{3}{2}} d t

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 3 \cdot \int t^{2} (t^{3} + 2)^{\frac{3}{2}} d t

Apply u-substitution

= 3 \cdot \int \frac{u ^{\frac{3}{2}}}{3} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 3 \cdot \frac{1}{3} \cdot \int u^{\frac{3}{2}} d u

Apply the Power Rule

= 3 \cdot \frac{1}{3} \cdot \frac{2}{5} u^{\frac{5}{2}}

Substitute back

u = t^{3} + 2

= 3 \cdot \frac{1}{3} \cdot \frac{2}{5} (t^{3} + 2)^{\frac{5}{2}}

Simplify

3 \cdot \frac{1}{3} \cdot \frac{2}{5} (t^{3} + 2)^{\frac{5}{2}} : \frac{2}{5} (t^{3} + 2)^{\frac{5}{2}}

= \frac{2}{5} (t^{3} + 2)^{\frac{5}{2}}

Add a constant to the solution

= \frac{2}{5} (t^{3} + 2)^{\frac{5}{2}} + C

What is the integral of 3t^2(t^3+2)^{3/2} ?
The integral of 3t^2(t^3+2)^{3/2} is 2/5 (t^3+2)^{5/2}+C