What is the integral of t^2sin(B)t ?

The integral of t^2sin(B)t is 1/4 t^4sin(B)+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

integral of t^2sin(B)t

\int t^{2} sin (B) t d t

\frac{1}{4} t^{4} sin (B) + C

Solution steps

\int t^{2} sin (B) t d t

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= sin (B) \cdot \int t t^{2} d t

Simplify

t t^{2} : t^{3}

= sin (B) \cdot \int t^{3} d t

Apply the Power Rule

= sin (B) \frac{t ^{4}}{4}

Simplify

sin (B) \frac{t ^{4}}{4} : \frac{1}{4} t^{4} sin (B)

= \frac{1}{4} t^{4} sin (B)

Add a constant to the solution

= \frac{1}{4} t^{4} sin (B) + C

What is the integral of t^2sin(B)t ?
The integral of t^2sin(B)t is 1/4 t^4sin(B)+C