What is the integral of (64)/(x^5) ?

The integral of (64)/(x^5) is -(16)/(x^4)+C

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integral of (64)/(x^5)

\int \frac{64}{x ^{5}} d x

- \frac{16}{x ^{4}} + C

Solution steps

\int \frac{64}{x ^{5}} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 64 \cdot \int \frac{1}{x ^{5}} d x

Apply the Power Rule

= 64 (- \frac{1}{4 x ^{4}})

Simplify

64 (- \frac{1}{4 x ^{4}}) : - \frac{16}{x ^{4}}

= - \frac{16}{x ^{4}}

Add a constant to the solution

= - \frac{16}{x ^{4}} + C

What is the integral of (64)/(x^5) ?
The integral of (64)/(x^5) is -(16)/(x^4)+C