What is the integral of (2x^2)/(a^2+x^2) ?

The integral of (2x^2)/(a^2+x^2) is -2aarctan(x/a)+2x+C

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integral of (2x^2)/(a^2+x^2)

\int \frac{2 x ^{2}}{a ^{2} + x ^{2}} d x

- 2 a arctan (\frac{x}{a}) + 2 x + C

Solution steps

\int \frac{2 x ^{2}}{a ^{2} + x ^{2}} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 2 \cdot \int \frac{x ^{2}}{a ^{2} + x ^{2}} d x

Apply Integral Substitution

= 2 \cdot \int \frac{a u ^{2}}{1 + u ^{2}} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 2 a \cdot \int \frac{u ^{2}}{1 + u ^{2}} d u

\frac{u ^{2}}{1 + u ^{2}} = - \frac{1}{1 + u ^{2}} + 1

= 2 a \cdot \int - \frac{1}{1 + u ^{2}} + 1 d u

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= 2 a (- \int \frac{1}{1 + u ^{2}} d u + \int 1 d u)

\int \frac{1}{1 + u ^{2}} d u = arctan (u)

\int 1 d u = u

= 2 a (- arctan (u) + u)

Substitute back

u = \frac{x}{a}

= 2 a (- arctan (\frac{x}{a}) + \frac{x}{a})

Simplify

2 a (- arctan (\frac{x}{a}) + \frac{x}{a}) : - 2 a arctan (\frac{x}{a}) + 2 x

= - 2 a arctan (\frac{x}{a}) + 2 x

Add a constant to the solution

= - 2 a arctan (\frac{x}{a}) + 2 x + C

What is the integral of (2x^2)/(a^2+x^2) ?
The integral of (2x^2)/(a^2+x^2) is -2aarctan(x/a)+2x+C