What is the integral of tan^2(x)tan^2(x) ?

The integral of tan^2(x)tan^2(x) is 1/3 tan^3(x)+x-tan(x)+C

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integral of tan^2(x)tan^2(x)

\int tan^{2} (x) tan^{2} (x) d x

\frac{1}{3} tan^{3} (x) + x - tan (x) + C

Solution steps

\int tan^{2} (x) tan^{2} (x) d x

Simplify

tan^{2} (x) tan^{2} (x) : tan^{4} (x)

= \int tan^{4} (x) d x

Apply Integral Reduction

= \frac{tan ^{3} ( x )}{3} - \int tan^{2} (x) d x

\int tan^{2} (x) d x = - x + tan (x)

= \frac{tan ^{3} ( x )}{3} - (- x + tan (x))

Simplify

\frac{tan ^{3} ( x )}{3} - (- x + tan (x)) : \frac{1}{3} tan^{3} (x) + x - tan (x)

= \frac{1}{3} tan^{3} (x) + x - tan (x)

Add a constant to the solution

= \frac{1}{3} tan^{3} (x) + x - tan (x) + C

What is the integral of tan^2(x)tan^2(x) ?
The integral of tan^2(x)tan^2(x) is 1/3 tan^3(x)+x-tan(x)+C