What is the integral of (2cos(x))/(1-sin^2(x)) ?

The integral of (2cos(x))/(1-sin^2(x)) is 2ln|tan(x)+sec(x)|+C

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integral of (2cos(x))/(1-sin^2(x))

\int \frac{2 cos ( x )}{1 - sin ^{2} ( x )} d x

2 ln ∣ tan (x) + sec (x) ∣ + C

Solution steps

\int \frac{2 cos ( x )}{1 - sin ^{2} ( x )} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 2 \cdot \int \frac{cos ( x )}{1 - sin ^{2} ( x )} d x

Rewrite using trig identities

= 2 \cdot \int sec (x) d x

Use the common integral:

\int sec (x) d x = ln ∣ tan (x) + sec (x) ∣

= 2 ln ∣ tan (x) + sec (x) ∣

Add a constant to the solution

= 2 ln ∣ tan (x) + sec (x) ∣ + C

What is the integral of (2cos(x))/(1-sin^2(x)) ?
The integral of (2cos(x))/(1-sin^2(x)) is 2ln|tan(x)+sec(x)|+C