What is the integral of (3-x)/(2x+1) ?

The integral of (3-x)/(2x+1) is -1/2 x+7/4 ln|2x+1|+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

integral of (3-x)/(2x+1)

\int \frac{3 - x}{2 x + 1} d x

- \frac{1}{2} x + \frac{7}{4} ln ∣ 2 x + 1 ∣ + C

Solution steps

\int \frac{3 - x}{2 x + 1} d x

Long division

\frac{3 - x}{2 x + 1} : - \frac{1}{2} + \frac{7}{2 ( 2 x + 1 )}

= \int - \frac{1}{2} + \frac{7}{2 ( 2 x + 1 )} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= - \int \frac{1}{2} d x + \int \frac{7}{2 ( 2 x + 1 )} d x

\int \frac{1}{2} d x = \frac{1}{2} x

\int \frac{7}{2 ( 2 x + 1 )} d x = \frac{7}{4} ln ∣ 2 x + 1 ∣

= - \frac{1}{2} x + \frac{7}{4} ln ∣ 2 x + 1 ∣

Add a constant to the solution

= - \frac{1}{2} x + \frac{7}{4} ln ∣ 2 x + 1 ∣ + C

What is the integral of (3-x)/(2x+1) ?
The integral of (3-x)/(2x+1) is -1/2 x+7/4 ln|2x+1|+C