What is the integral of xy^{-2} ?

The integral of xy^{-2} is (x^2)/(2y^2)+C

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integral of xy^{-2}

\int x y^{- 2}

\frac{x ^{2}}{2 y ^{2}} + C

Solution steps

\int x y^{- 2} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= y^{- 2} \cdot \int x d x

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

= \frac{1}{y ^{2}} \cdot \int x d x

Apply the Power Rule

= \frac{1}{y ^{2}} \cdot \frac{x ^{2}}{2}

Simplify

\frac{1}{y ^{2}} \cdot \frac{x ^{2}}{2} : \frac{x ^{2}}{2 y ^{2}}

= \frac{x ^{2}}{2 y ^{2}}

Add a constant to the solution

= \frac{x ^{2}}{2 y ^{2}} + C