What is the integral of ()/(\sqrt[3]{z^2)} ?

The integral of ()/(\sqrt[3]{z^2)} is (dz)/(z^{2/3)}x+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

integral of ()/(\sqrt[3]{z^2)}

\frac{d z}{z ^{\frac{2}{3}}} x + C

Solution steps

Integral of a constant:

\int a d x = a x

Apply radical rule:

assuming

a \geq 0

= \frac{d z}{z ^{\frac{2}{3}}} x

Add a constant to the solution

= \frac{d z}{z ^{\frac{2}{3}}} x + C

What is the integral of ()/(\sqrt[3]{z^2)} ?
The integral of ()/(\sqrt[3]{z^2)} is (dz)/(z^{2/3)}x+C