derivative of sqrt(7x+3)

解答

\frac{d}{d x} (7 x + 3)

\frac{7}{2 7 x + 3}

求解步骤

\frac{d}{d x} (7 x + 3)

使用连锁律:

\frac{1}{2 7 x + 3} \frac{d}{d x} (7 x + 3)

= \frac{1}{2 7 x + 3} \frac{d}{d x} (7 x + 3)

\frac{d}{d x} (7 x + 3) = 7

= \frac{1}{2 7 x + 3} \cdot 7

化简

\frac{1}{2 7 x + 3} \cdot 7 : \frac{7}{2 7 x + 3}

= \frac{7}{2 7 x + 3}

n \to \infty lim (\frac{3 n ^{0.4 + 1} + 7 n}{3 n ^{0.4} + 7 n})

y^{^{''}} + 5 y^{^{'}} = e^{- t}, y (0) = - 0, y^{^{'}} (0) = 1

\int \frac{- y}{cot ( x )} d x

y^{^{''}} + 2 y^{^{'}} - 24 y = 0

x y + y^{^{'}} = 76 x