y^'-8/x y=y^3 1/(x^{12)}

Lösung

y^{^{'}} - \frac{8}{x} y = y^{3} \frac{1}{x ^{12}}

y = \frac{5 x ^{8}}{- 2 x ^{5} + c _{1}}, y = - \frac{5 x ^{8}}{- 2 x ^{5} + c _{1}}

Schritte zur Lösung

y^{'} (x) - \frac{8}{x} y = y^{3} \frac{1}{x ^{12}}

Solve Bernoulli ODE:

y = \frac{5 x ^{8}}{- 2 x ^{5} + c _{1}}, y = - \frac{5 x ^{8}}{- 2 x ^{5} + c _{1}}

y = \frac{5 x ^{8}}{- 2 x ^{5} + c _{1}}, y = - \frac{5 x ^{8}}{- 2 x ^{5} + c _{1}}

a re a y = x^{2}, x = y^{2}

3 x y^{^{'}} - 15 y = x^{- 1}

n = 9 \sum \infty (\frac{1}{7})^{n}

\int_{- \infty}^{0} 0 d x

x \to 9 lim (\frac{1}{x + 3})