해법
∫x3−27x3+2x2−3x+1dx
해법
x−2714ln4x2+12x+36+32lnx3−27+2719ln∣x−3∣−931arctan(332x+31)−3arctan(332x+31)−61(−ln4x2+12x+36+23arctan(332x+31))+C
솔루션 단계
∫x3−27x3+2x2−3x+1dx
x3−27x3+2x2−3x+1확대한다:x3−27x3+x3−272x2−x3−273x+x3−271
합계 규칙 적용: ∫f(x)±g(x)dx=∫f(x)dx±∫g(x)dx=∫x3−27x3dx+∫x3−272x2dx−∫x3−273xdx+∫x3−271dx
∫x3−27x3dx=x+ln∣x−3∣−21ln4x2+12x+36−3arctan(332x+31)
∫x3−272x2dx=32lnx3−27
∫x3−273xdx=3(91ln∣x−3∣+181(−ln4x2+12x+36+23arctan(331(2x+3))))
∫x3−271dx=271ln∣x−3∣−541ln4x2+12x+36−931arctan(332x+31)
=x+ln∣x−3∣−21ln4x2+12x+36−3arctan(332x+31)+32lnx3−27−3(91ln∣x−3∣+181(−ln4x2+12x+36+23arctan(331(2x+3))))+271ln∣x−3∣−541ln4x2+12x+36−931arctan(332x+31)
x+ln∣x−3∣−21ln4x2+12x+36−3arctan(332x+31)+32lnx3−27−3(91ln∣x−3∣+181(−ln4x2+12x+36+23arctan(331(2x+3))))+271ln∣x−3∣−541ln4x2+12x+36−931arctan(332x+31)간소화하다 :x−2714ln4x2+12x+36+32lnx3−27+2719ln∣x−3∣−931arctan(332x+31)−3arctan(332x+31)−61(−ln4x2+12x+36+23arctan(332x+31))
=x−2714ln4x2+12x+36+32lnx3−27+2719ln∣x−3∣−931arctan(332x+31)−3arctan(332x+31)−61(−ln4x2+12x+36+23arctan(332x+31))
솔루션에 상수 추가=x−2714ln4x2+12x+36+32lnx3−27+2719ln∣x−3∣−931arctan(332x+31)−3arctan(332x+31)−61(−ln4x2+12x+36+23arctan(332x+31))+C