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Popular Calculus >

y^'=y-x^2+1,y(0)=0

Solution

y^{^{'}} = y - x^{2} + 1, y (0) = 0

Solution

y = x^{2} + 2 x + 1 - e^{x}

Solution steps

y^{'} (x) = y - x^{2} + 1

Solve linear ODE:

y = x^{2} + 2 x + 1 - e^{x}

y = x^{2} + 2 x + 1 - e^{x}

Graph

Popular Examples

integral of (b-x)/x

\int \frac{b - x}{x} d x

(\partial)/(\partial x)((e^y)/(x+y^3))

\frac{\partial}{\partial x} (\frac{e ^{y}}{x + y ^{3}})

integral of 1/(a-x)

\int \frac{1}{a - x} d x

integral of (x+2)sqrt(4x+x^2)

\int (x + 2) 4 x + x^{2} d x

integral of 1/(n^3)

\int \frac{1}{n ^{3}}

Frequently Asked Questions (FAQ)

What is the solution for y^'=y-x^2+1,y(0)=0 ?
The solution for y^'=y-x^2+1,y(0)=0 is y=x^2+2x+1-e^x