What is the derivative of C(x)=-0.01x^2+7.2x-163 ?

The derivative of C(x)=-0.01x^2+7.2x-163 is -0.02x+7.2

What is the first derivative of C(x)=-0.01x^2+7.2x-163 ?

The first derivative of C(x)=-0.01x^2+7.2x-163 is -0.02x+7.2

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derivative

- 0.02 x + 7.2

Solution steps

\frac{d}{d x} (- 0.01 x^{2} + 7.2 x - 163)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= - \frac{d}{d x} (0.01 x^{2}) + \frac{d}{d x} (7.2 x) - \frac{d}{d x} (163)

\frac{d}{d x} (0.01 x^{2}) = 0.02 x

\frac{d}{d x} (7.2 x) = 7.2

\frac{d}{d x} (163) = 0

= - 0.02 x + 7.2 - 0

Simplify

= - 0.02 x + 7.2

What is the derivative of C(x)=-0.01x^2+7.2x-163 ?
The derivative of C(x)=-0.01x^2+7.2x-163 is -0.02x+7.2
What is the first derivative of C(x)=-0.01x^2+7.2x-163 ?
The first derivative of C(x)=-0.01x^2+7.2x-163 is -0.02x+7.2