{
"query": {
"display": "$$\\int\\:12\\left(y^{4}+4y^{2}+8\\right)^{2}\\left(y^{3}+2y\\right)dy$$",
"symbolab_question": "BIG_OPERATOR#\\int 12(y^{4}+4y^{2}+8)^{2}(y^{3}+2y)dy"
},
"solution": {
"level": "PERFORMED",
"subject": "Calculus",
"topic": "Integrals",
"subTopic": "Indefinite Integrals",
"default": "(y^{4}+4y^{2}+8)^{3}+C",
"meta": {
"showVerify": true
}
},
"steps": {
"type": "interim",
"title": "$$\\int\\:12\\left(y^{4}+4y^{2}+8\\right)^{2}\\left(y^{3}+2y\\right)dy=\\left(y^{4}+4y^{2}+8\\right)^{3}+C$$",
"input": "\\int\\:12\\left(y^{4}+4y^{2}+8\\right)^{2}\\left(y^{3}+2y\\right)dy",
"steps": [
{
"type": "step",
"primary": "Take the constant out: $$\\int{a\\cdot{f\\left(x\\right)}dx}=a\\cdot\\int{f\\left(x\\right)dx}$$",
"result": "=12\\cdot\\:\\int\\:\\left(y^{4}+4y^{2}+8\\right)^{2}\\left(y^{3}+2y\\right)dy"
},
{
"type": "interim",
"title": "Apply u-substitution",
"input": "\\int\\:\\left(y^{4}+4y^{2}+8\\right)^{2}\\left(y^{3}+2y\\right)dy",
"steps": [
{
"type": "definition",
"title": "Integral Substitution definition",
"text": "$$\\int\\:f\\left(g\\left(x\\right)\\right)\\cdot\\:g'\\left(x\\right)dx=\\int\\:f\\left(u\\right)du,\\:\\quad\\:u=g\\left(x\\right)$$",
"secondary": [
"Substitute: $$u=y^{4}+4y^{2}+8$$"
]
},
{
"type": "interim",
"title": "$$\\frac{du}{dy}=4y^{3}+8y$$",
"input": "\\frac{d}{dy}\\left(y^{4}+4y^{2}+8\\right)",
"steps": [
{
"type": "step",
"primary": "Apply the Sum/Difference Rule: $$\\left(f{\\pm}g\\right)'=f'{\\pm}g'$$",
"result": "=\\frac{d}{dy}\\left(y^{4}\\right)+\\frac{d}{dy}\\left(4y^{2}\\right)+\\frac{d}{dy}\\left(8\\right)"
},
{
"type": "interim",
"title": "$$\\frac{d}{dy}\\left(y^{4}\\right)=4y^{3}$$",
"input": "\\frac{d}{dy}\\left(y^{4}\\right)",
"steps": [
{
"type": "step",
"primary": "Apply the Power Rule: $$\\frac{d}{dx}\\left(x^a\\right)=a{\\cdot}x^{a-1}$$",
"result": "=4y^{4-1}",
"meta": {
"practiceLink": "/practice/derivatives-practice#area=main&subtopic=Power%20Rule",
"practiceTopic": "Power Rule"
}
},
{
"type": "step",
"primary": "Simplify",
"result": "=4y^{3}",
"meta": {
"solvingClass": "Solver"
}
}
],
"meta": {
"solvingClass": "Derivatives",
"interimType": "Derivatives",
"gptData": "pG0PljGlka7rWtIVHz2xymbOTBTIQkBEGSNjyYYsjjDErT97kX84sZPuiUzCW6s79Kg+idP5vLVrjUll6eMdYkxhypVUiG3atzXmTPYRdMak3hxk9aCfAWodBRxXgUexg78CTHCDA/lpFNIL9ZtcH/8//6/nV5O4fb8Xgwi7maozYMeOxPk/lnQlt7VFBYbY90eL1Lx58KCcIoFHnNQcCw=="
}
},
{
"type": "interim",
"title": "$$\\frac{d}{dy}\\left(4y^{2}\\right)=8y$$",
"input": "\\frac{d}{dy}\\left(4y^{2}\\right)",
"steps": [
{
"type": "step",
"primary": "Take the constant out: $$\\left(a{\\cdot}f\\right)'=a{\\cdot}f'$$",
"result": "=4\\frac{d}{dy}\\left(y^{2}\\right)"
},
{
"type": "step",
"primary": "Apply the Power Rule: $$\\frac{d}{dx}\\left(x^a\\right)=a{\\cdot}x^{a-1}$$",
"result": "=4\\cdot\\:2y^{2-1}",
"meta": {
"practiceLink": "/practice/derivatives-practice#area=main&subtopic=Power%20Rule",
"practiceTopic": "Power Rule"
}
},
{
"type": "step",
"primary": "Simplify",
"result": "=8y",
"meta": {
"solvingClass": "Solver"
}
}
],
"meta": {
"solvingClass": "Derivatives",
"interimType": "Derivatives",
"gptData": "pG0PljGlka7rWtIVHz2xymbOTBTIQkBEGSNjyYYsjjDErT97kX84sZPuiUzCW6s79Kg+idP5vLVrjUll6eMdYrqt0YuaSL2Rm1UYrS/xAkGTdaV09PMxEKZ9FieghTFwZ2fGfNjpdOxZtpqB42U58KN6Hv6MoTMtvtU0IQwXdn/ap0oHImbv6f5GTOTwYbXNksmWoz/3QD0mF0Vr38VpIg=="
}
},
{
"type": "interim",
"title": "$$\\frac{d}{dy}\\left(8\\right)=0$$",
"input": "\\frac{d}{dy}\\left(8\\right)",
"steps": [
{
"type": "step",
"primary": "Derivative of a constant: $$\\frac{d}{dx}\\left({a}\\right)=0$$",
"result": "=0"
}
],
"meta": {
"solvingClass": "Derivatives",
"interimType": "Derivatives",
"gptData": "pG0PljGlka7rWtIVHz2xymbOTBTIQkBEGSNjyYYsjjDErT97kX84sZPuiUzCW6s79Kg+idP5vLVrjUll6eMdYkxl41yJ3wnOwbaINEo5sfFJ8Vk6wvKjVnTtwWT18bQnz7FeFrf3rcM8IZlDz2c0dm5O2bEw0Ql6ne7k1AUriTtpgS80+Yza2KfnoIr71kZr"
}
},
{
"type": "step",
"result": "=4y^{3}+8y+0"
},
{
"type": "step",
"primary": "Simplify",
"result": "=4y^{3}+8y",
"meta": {
"solvingClass": "Solver"
}
}
],
"meta": {
"solvingClass": "Derivatives",
"interimType": "Derivatives"
}
},
{
"type": "step",
"primary": "$$\\quad\\Rightarrow\\:du=4y^{3}+8ydy$$"
},
{
"type": "step",
"primary": "$$\\quad\\Rightarrow\\:dy=\\frac{1}{4y^{3}+8y}du$$"
},
{
"type": "step",
"result": "=\\int\\:u^{2}\\left(y^{3}+2y\\right)\\frac{1}{4y^{3}+8y}du"
},
{
"type": "interim",
"title": "Simplify $$u^{2}\\left(y^{3}+2y\\right)\\frac{1}{4y^{3}+8y}:{\\quad}\\frac{u^{2}}{4}$$",
"input": "u^{2}\\left(y^{3}+2y\\right)\\frac{1}{4y^{3}+8y}",
"steps": [
{
"type": "step",
"primary": "Multiply fractions: $$a\\cdot\\frac{b}{c}=\\frac{a\\:\\cdot\\:b}{c}$$",
"result": "=\\frac{1\\cdot\\:u^{2}\\left(y^{3}+2y\\right)}{4y^{3}+8y}"
},
{
"type": "step",
"primary": "Multiply: $$1\\cdot\\:u^{2}=u^{2}$$",
"result": "=\\frac{u^{2}\\left(y^{3}+2y\\right)}{4y^{3}+8y}"
},
{
"type": "interim",
"title": "Factor $$y^{3}+2y:{\\quad}y\\left(y^{2}+2\\right)$$",
"input": "y^{3}+2y",
"result": "=\\frac{u^{2}y\\left(y^{2}+2\\right)}{4y^{3}+8y}",
"steps": [
{
"type": "step",
"primary": "Apply exponent rule: $$a^{b+c}=a^{b}a^{c}$$",
"secondary": [
"$$y^{3}=yy^{2}$$"
],
"result": "=yy^{2}+2y",
"meta": {
"practiceLink": "/practice/exponent-practice",
"practiceTopic": "Expand FOIL"
}
},
{
"type": "step",
"primary": "Factor out common term $$y$$",
"result": "=y\\left(y^{2}+2\\right)",
"meta": {
"practiceLink": "/practice/factoring-practice",
"practiceTopic": "Factoring"
}
}
],
"meta": {
"interimType": "Algebraic Manipulation Factor Title 1Eq"
}
},
{
"type": "interim",
"title": "Factor $$4y^{3}+8y:{\\quad}4y\\left(y^{2}+2\\right)$$",
"input": "4y^{3}+8y",
"result": "=\\frac{u^{2}y\\left(y^{2}+2\\right)}{4y\\left(y^{2}+2\\right)}",
"steps": [
{
"type": "step",
"primary": "Apply exponent rule: $$a^{b+c}=a^{b}a^{c}$$",
"secondary": [
"$$y^{3}=yy^{2}$$"
],
"result": "=4yy^{2}+8y",
"meta": {
"practiceLink": "/practice/exponent-practice",
"practiceTopic": "Expand FOIL"
}
},
{
"type": "step",
"primary": "Rewrite as",
"result": "=4yy^{2}+2\\cdot\\:4y"
},
{
"type": "step",
"primary": "Factor out common term $$4y$$",
"result": "=4y\\left(y^{2}+2\\right)",
"meta": {
"practiceLink": "/practice/factoring-practice",
"practiceTopic": "Factoring"
}
}
],
"meta": {
"interimType": "Algebraic Manipulation Factor Title 1Eq"
}
},
{
"type": "interim",
"title": "Cancel $$\\frac{u^{2}y\\left(y^{2}+2\\right)}{4y\\left(y^{2}+2\\right)}:{\\quad}\\frac{u^{2}}{4}$$",
"input": "\\frac{u^{2}y\\left(y^{2}+2\\right)}{4y\\left(y^{2}+2\\right)}",
"result": "=\\frac{u^{2}}{4}",
"steps": [
{
"type": "step",
"primary": "Cancel the common factor: $$y$$",
"result": "=\\frac{u^{2}\\left(y^{2}+2\\right)}{4\\left(y^{2}+2\\right)}"
},
{
"type": "step",
"primary": "Cancel the common factor: $$y^{2}+2$$",
"result": "=\\frac{u^{2}}{4}"
}
],
"meta": {
"interimType": "Generic Cancel Title 1Eq",
"gptData": "pG0PljGlka7rWtIVHz2xymbOTBTIQkBEGSNjyYYsjjDErT97kX84sZPuiUzCW6s79Kg+idP5vLVrjUll6eMdYnAwSLBELR8i9m6G4P+CisrAbMFVLe2Vt4pfIAwMbkqLVdNK6b/PmQukzNdLVQkh7GCeK3dtjkfH1uaY9WqMYsCuirxfJj7yzhlUWCbvijZZ1sD7NfhsPe7eDHrmjY0mE2J/JAWPJQkixCwxTVklZhNwMEiwRC0fIvZuhuD/gorK63VPOevF/u6/soDtZLyG8SS3daIZHtloJpe/PvtsyNI="
}
}
],
"meta": {
"solvingClass": "Solver",
"interimType": "Algebraic Manipulation Simplify Title 1Eq"
}
},
{
"type": "step",
"result": "=\\int\\:\\frac{u^{2}}{4}du"
}
],
"meta": {
"interimType": "Integral U Substitution 1Eq",
"gptData": "pG0PljGlka7rWtIVHz2xymbOTBTIQkBEGSNjyYYsjjDErT97kX84sZPuiUzCW6s7l7+Hp9GxvB/5I+4/5L7s7y4NDkPMEyDrWlXR5OwenVlB/rfq1RcQ1BqqvOJn9yVqHI5S0StY1FdtOqqOPr0Te8kZykkSQR7JxF6tcEv88MO4fClF/YTdtcCRNeh/zX2cdnL+ucZY+BVjv4wL+wJtQuD2/7SwQCayxtHsn6FD9znvbBmbuQNTF0TphKZ8RuvaR7hM6KADkFDngi1m57r+mR5n4zu7ICtqiQHGrVYWXPk="
}
},
{
"type": "step",
"result": "=12\\cdot\\:\\int\\:\\frac{u^{2}}{4}du"
},
{
"type": "step",
"primary": "Take the constant out: $$\\int{a\\cdot{f\\left(x\\right)}dx}=a\\cdot\\int{f\\left(x\\right)dx}$$",
"result": "=12\\cdot\\:\\frac{1}{4}\\cdot\\:\\int\\:u^{2}du"
},
{
"type": "interim",
"title": "Apply the Power Rule",
"input": "\\int\\:u^{2}du",
"result": "=12\\cdot\\:\\frac{1}{4}\\cdot\\:\\frac{u^{3}}{3}",
"steps": [
{
"type": "step",
"primary": "Apply the Power Rule: $$\\int{x^{a}}dx=\\frac{x^{a+1}}{a+1},\\:\\quad\\:a\\neq{-1}$$",
"result": "=\\frac{u^{2+1}}{2+1}"
},
{
"type": "interim",
"title": "Simplify $$\\frac{u^{2+1}}{2+1}:{\\quad}\\frac{u^{3}}{3}$$",
"input": "\\frac{u^{2+1}}{2+1}",
"steps": [
{
"type": "step",
"primary": "Add the numbers: $$2+1=3$$",
"result": "=\\frac{u^{3}}{3}"
}
],
"meta": {
"solvingClass": "Solver",
"interimType": "Algebraic Manipulation Simplify Title 1Eq"
}
},
{
"type": "step",
"result": "=\\frac{u^{3}}{3}"
}
],
"meta": {
"interimType": "Power Rule Top 0Eq",
"gptData": "pG0PljGlka7rWtIVHz2xymbOTBTIQkBEGSNjyYYsjjDErT97kX84sZPuiUzCW6s7l7+Hp9GxvB/5I+4/5L7s7ztMnkJqJUs4Qp2osi+oqZ+o/JI5bBgpgExN510TA5cyodqSCYnUP+KiNK7E2zlYiE/QYMzREewyYhmRoDar7ofEE1c1KRzl1GtEOEJ8QtOggQUxJPyUNnGfVirkcwpVOw39JmBCMfU6hqFWM4cbYeuPws1TZ9p9GAZMOucM4Sei"
}
},
{
"type": "step",
"primary": "Substitute back $$u=y^{4}+4y^{2}+8$$",
"result": "=12\\cdot\\:\\frac{1}{4}\\cdot\\:\\frac{\\left(y^{4}+4y^{2}+8\\right)^{3}}{3}"
},
{
"type": "interim",
"title": "Simplify $$12\\cdot\\:\\frac{1}{4}\\cdot\\:\\frac{\\left(y^{4}+4y^{2}+8\\right)^{3}}{3}:{\\quad}\\left(y^{4}+4y^{2}+8\\right)^{3}$$",
"input": "12\\cdot\\:\\frac{1}{4}\\cdot\\:\\frac{\\left(y^{4}+4y^{2}+8\\right)^{3}}{3}",
"result": "=\\left(y^{4}+4y^{2}+8\\right)^{3}",
"steps": [
{
"type": "step",
"primary": "Multiply fractions: $$a\\cdot\\frac{b}{c}\\cdot\\frac{d}{e}=\\frac{a\\:\\cdot\\:b\\:\\cdot\\:d}{c\\:\\cdot\\:e}$$",
"result": "=\\frac{1\\cdot\\:\\left(y^{4}+4y^{2}+8\\right)^{3}\\cdot\\:12}{4\\cdot\\:3}"
},
{
"type": "step",
"primary": "Refine",
"result": "=\\frac{12\\left(y^{4}+4y^{2}+8\\right)^{3}}{12}"
},
{
"type": "step",
"primary": "Divide the numbers: $$\\frac{12}{12}=1$$",
"result": "=\\left(y^{4}+4y^{2}+8\\right)^{3}"
}
],
"meta": {
"solvingClass": "Solver",
"interimType": "Generic Simplify Specific 1Eq",
"gptData": "pG0PljGlka7rWtIVHz2xymbOTBTIQkBEGSNjyYYsjjDErT97kX84sZPuiUzCW6s7X9Re+PckSoemCIRQQUfDdRKeGTTEZItbVonaoPZxnfW4BKkWMzJDVj+NkZEF+9jUzDkaBtFcVK1CC0iFZmmWlN6GQqufR6tr2vPxOUv7H++NYxOQPujgok9wizXRQ0bKpkSO8SEQ2VyMAzM4ybVPNaN6Hv6MoTMtvtU0IQwXdn9szOhN37mcRdV5CgGGkVwgmYMUHWuuN2/A63BuN3hQoikJfK6myGFkAjFYK+SmYXZrfQkkunM4TFS4yddbdBo2bdn7epyh2nsXoTCgpWwSyQ=="
}
},
{
"type": "step",
"primary": "Add a constant to the solution",
"result": "=\\left(y^{4}+4y^{2}+8\\right)^{3}+C",
"meta": {
"title": {
"extension": "If $$\\frac{dF\\left(x\\right)}{dx}=f\\left(x\\right)$$ then $$\\int{f\\left(x\\right)}dx=F\\left(x\\right)+C$$"
}
}
}
],
"meta": {
"solvingClass": "Integrals",
"practiceLink": "/practice/integration-practice#area=main&subtopic=Substitution",
"practiceTopic": "Integral Substitution"
}
},
"plot_output": {
"meta": {
"plotInfo": {
"variable": "y",
"plotRequest": "y=(y^{4}+4y^{2}+8)^{3}+C"
},
"showViewLarger": true
}
},
"meta": {
"showVerify": true
}
}
Solution
Solution
Solution steps
Take the constant out:
Apply u-substitution
Take the constant out:
Apply the Power Rule
Substitute back
Simplify
Add a constant to the solution
Graph
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Frequently Asked Questions (FAQ)
What is the integral of 12(y^4+4y^2+8)^2(y^3+2y) ?
The integral of 12(y^4+4y^2+8)^2(y^3+2y) is (y^4+4y^2+8)^3+C