derivative of 0.006x^3+0.07x^2+18x+600

Lösung

\frac{d}{d x} (0.006 x^{3} + 0.07 x^{2} + 18 x + 600)

0.018 x^{2} + 0.14 x + 18

Schritte zur Lösung

\frac{d}{d x} (0.006 x^{3} + 0.07 x^{2} + 18 x + 600)

Wende die Summen-/Differenzregel an:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (0.006 x^{3}) + \frac{d}{d x} (0.07 x^{2}) + \frac{d}{d x} (18 x) + \frac{d}{d x} (600)

\frac{d}{d x} (0.006 x^{3}) = 0.018 x^{2}

\frac{d}{d x} (0.07 x^{2}) = 0.14 x

\frac{d}{d x} (18 x) = 18

\frac{d}{d x} (600) = 0

= 0.018 x^{2} + 0.14 x + 18 + 0

Vereinfache

= 0.018 x^{2} + 0.14 x + 18

\frac{d y}{d x} = y (2 x - 5)

x \to 4 lim (\frac{x ^{2} - 8 x + 16}{x - 4})

d er i v a t i v e cos (5 x)

y^{^{'}} + 2 y = 6 e^{x}

\frac{d y}{d x} = x e^{- y} + 10 e^{- y}