integral from-6 to 1 of |x+4|

Lösung

\int_{- 6}^{1} ∣ x + 4 ∣ d x

\frac{29}{2}

Dezimale

14.5

Schritte zur Lösung

\int_{- 6}^{1} ∣ x + 4 ∣ d x

Entferne die Extremwerte

= \int_{- 6}^{- 4} - x - 4 d x + \int_{- 4}^{1} x + 4 d x

\int_{- 6}^{- 4} - x - 4 d x = 2

\int_{- 4}^{1} x + 4 d x = \frac{25}{2}

= 2 + \frac{25}{2}

Vereinfache

2 + \frac{25}{2} : \frac{29}{2}

= \frac{29}{2}

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