integral from 1 to 2 of 1/(x^2)-1/x

Lösung

\int_{1}^{2} \frac{1}{x ^{2}} - \frac{1}{x} d x

\frac{1}{2} - ln (2)

Dezimale

- 0.19314 \dots

Schritte zur Lösung

\int_{1}^{2} \frac{1}{x ^{2}} - \frac{1}{x} d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{1}^{2} \frac{1}{x ^{2}} d x - \int_{1}^{2} \frac{1}{x} d x

\int_{1}^{2} \frac{1}{x ^{2}} d x = \frac{1}{2}

\int_{1}^{2} \frac{1}{x} d x = ln (2)

= \frac{1}{2} - ln (2)

\int_{0}^{20} \frac{1}{16} x e^{- \frac{x}{4}} d x

\int_{0}^{\frac{1}{2}} 3 y d y

\int_{0}^{2} 3 t t^{2} + 1 d t

\int_{1}^{x} \frac{e ^{x t}}{t} d t

\int_{0}^{3} x sin (π x^{2}) d x