What is laplacetransform 4te^{-3t} ?

The answer to laplacetransform 4te^{-3t} is 4/((s+3)^2)

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laplacetransform 4te^{-3t}

laplace transform

4 t e^{- 3 t}

\frac{4}{( s + 3 ) ^{2}}

Solution steps

L {4 e^{- 3 t} t}

Use the constant multiplication property of Laplace Transform:

For function

f (t)

and constant

a : L {a \cdot f (t)} = a \cdot L {f (t)}

= 4 L {t e^{- 3 t}}

L {t e^{- 3 t}} : \frac{1}{( s + 3 ) ^{2}}

= 4 \cdot \frac{1}{( s + 3 ) ^{2}}

Refine

4 \frac{1}{( s + 3 ) ^{2}} : \frac{4}{( s + 3 ) ^{2}}

= \frac{4}{( s + 3 ) ^{2}}

n = 1 \sum \infty n^{n} x^{n}

y^{^{'}} + 8 (tan (8 x)) y = - 5 cos (8 x)

x \to \infty lim (\frac{x 7 + 1}{x 7})

t an g e n t y = x^{2} + 7

(ln (2 x + 1))^{^{'}}

What is laplacetransform 4te^{-3t} ?
The answer to laplacetransform 4te^{-3t} is 4/((s+3)^2)