ja

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

人気のある微分積分 >

integral from 0 to 1 of xsqrt(11x^2+25)

解

\int_{0}^{1} x 11 x^{2} + 25 d x

解

\frac{91}{33}

+1

十進法表記

2.75757 \dots

解答ステップ

\int_{0}^{1} x 11 x^{2} + 25 d x

u置換積分法を適用する

= \int_{25}^{36} \frac{u}{22} d u

定数を除く:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{22} \cdot \int_{25}^{36} u d u

べき乗則を適用する

= \frac{1}{22} [\frac{2}{3} u^{\frac{3}{2}}]_{25}^{36}

限度を計算する:

\frac{182}{3}

= \frac{1}{22} \cdot \frac{182}{3}

簡素化

= \frac{91}{33}

グラフ

人気の例

integral from 0 to x of 1/((1-x)^3)

\int_{0}^{x} \frac{1}{( 1 - x ) ^{3}} d x

integral from 0 to 2 of 5e^x+9cos(x)

\int_{0}^{2} 5 e^{x} + 9 cos (x) d x

integral from 0 to pi of cos(7x)

\int_{0}^{π} cos (7 x) d x

integral from 0 to 1 of 3r

\int_{0}^{1} 3 r d r

integral from 0 to 1 of (8-9x^2)

\int_{0}^{1} (8 - 9 x^{2}) d x