{
"query": {
"display": "$$\\frac{d}{dx}\\left(\\ln\\left(\\frac{1}{1-x}\\right)\\right)$$",
"symbolab_question": "DERIVATIVE#\\frac{d}{dx}(\\ln(\\frac{1}{1-x}))"
},
"solution": {
"level": "PERFORMED",
"subject": "Calculus",
"topic": "Derivatives",
"subTopic": "Derivatives",
"default": "\\frac{1}{1-x}",
"meta": {
"showVerify": true
}
},
"steps": {
"type": "interim",
"title": "$$\\frac{d}{dx}\\left(\\ln\\left(\\frac{1}{1-x}\\right)\\right)=\\frac{1}{1-x}$$",
"input": "\\frac{d}{dx}\\left(\\ln\\left(\\frac{1}{1-x}\\right)\\right)",
"steps": [
{
"type": "interim",
"title": "Simplify $$\\ln\\left(\\frac{1}{1-x}\\right):{\\quad}-\\ln\\left(1-x\\right)$$",
"input": "\\ln\\left(\\frac{1}{1-x}\\right)",
"steps": [
{
"type": "step",
"primary": "Apply log rule: $$\\log_{a}\\left(\\frac{1}{x}\\right)=-\\log_{a}\\left(x\\right)$$",
"result": "=-\\ln\\left(-x+1\\right)",
"meta": {
"practiceLink": "/practice/logarithms-practice",
"practiceTopic": "Expand FOIL"
}
}
],
"meta": {
"solvingClass": "Solver",
"interimType": "Algebraic Manipulation Simplify Title 1Eq"
}
},
{
"type": "step",
"result": "=\\frac{d}{dx}\\left(-\\ln\\left(1-x\\right)\\right)"
},
{
"type": "step",
"primary": "Take the constant out: $$\\left(a{\\cdot}f\\right)'=a{\\cdot}f'$$",
"result": "=-\\frac{d}{dx}\\left(\\ln\\left(1-x\\right)\\right)"
},
{
"type": "interim",
"title": "Apply the chain rule:$${\\quad}\\frac{1}{1-x}\\frac{d}{dx}\\left(1-x\\right)$$",
"input": "\\frac{d}{dx}\\left(\\ln\\left(1-x\\right)\\right)",
"result": "=\\frac{1}{1-x}\\frac{d}{dx}\\left(1-x\\right)",
"steps": [
{
"type": "step",
"primary": "Apply the chain rule: $$\\frac{df\\left(u\\right)}{dx}=\\frac{df}{du}\\cdot\\frac{du}{dx}$$",
"secondary": [
"$$f=\\ln\\left(u\\right),\\:\\:u=1-x$$"
],
"result": "=\\frac{d}{du}\\left(\\ln\\left(u\\right)\\right)\\frac{d}{dx}\\left(1-x\\right)",
"meta": {
"practiceLink": "/practice/derivatives-practice#area=main&subtopic=Chain%20Rule",
"practiceTopic": "Chain Rule"
}
},
{
"type": "interim",
"title": "$$\\frac{d}{du}\\left(\\ln\\left(u\\right)\\right)=\\frac{1}{u}$$",
"input": "\\frac{d}{du}\\left(\\ln\\left(u\\right)\\right)",
"steps": [
{
"type": "step",
"primary": "Apply the common derivative: $$\\frac{d}{du}\\left(\\ln\\left(u\\right)\\right)=\\frac{1}{u}$$",
"result": "=\\frac{1}{u}"
}
],
"meta": {
"solvingClass": "Derivatives",
"interimType": "Derivatives",
"gptData": "pG0PljGlka7rWtIVHz2xymbOTBTIQkBEGSNjyYYsjjDErT97kX84sZPuiUzCW6s79Kg+idP5vLVrjUll6eMdYoqTCAmruKWcJsn66ZPDMT8cjlLRK1jUV206qo4+vRN78rEus7TgCihQBF5omOFkJq1PlbV5jLoKv9solFCc4blTW26qciuyUBGXQExCUedYd9mDo5FIvzrirtH7/W8pPUxk6YPA4jUd3Af4X0JJJ64="
}
},
{
"type": "step",
"result": "=\\frac{1}{u}\\frac{d}{dx}\\left(1-x\\right)"
},
{
"type": "step",
"primary": "Substitute back $$u=1-x$$",
"result": "=\\frac{1}{1-x}\\frac{d}{dx}\\left(1-x\\right)"
}
],
"meta": {
"interimType": "Derivative Chain Rule 0Eq",
"gptData": "pG0PljGlka7rWtIVHz2xymbOTBTIQkBEGSNjyYYsjjDErT97kX84sZPuiUzCW6s79Kg+idP5vLVrjUll6eMdYnnZDzt2oZLUVmou50nACzqQp7tdIFyr1eVqMMLZHDTGOK1n91tyBoBr/ZHP0eNC/RSNU68ZmiYZN//Vg53tMEyDWCSqwfKB+LJy+pyziHhw6WgDs/9/Ow4Ia+3J0uMrXd4bBmgMCMR/fNG/lmu/V52qkIX6kseCKdEth+cILnwyMX9qYKk0viGvXKHsQSVFeoi+ZPlQ6KBam0kIORBN9aU="
}
},
{
"type": "interim",
"title": "$$\\frac{d}{dx}\\left(1-x\\right)=-1$$",
"input": "\\frac{d}{dx}\\left(1-x\\right)",
"steps": [
{
"type": "step",
"primary": "Apply the Sum/Difference Rule: $$\\left(f{\\pm}g\\right)'=f'{\\pm}g'$$",
"result": "=\\frac{d}{dx}\\left(1\\right)-\\frac{dx}{dx}"
},
{
"type": "interim",
"title": "$$\\frac{d}{dx}\\left(1\\right)=0$$",
"input": "\\frac{d}{dx}\\left(1\\right)",
"steps": [
{
"type": "step",
"primary": "Derivative of a constant: $$\\frac{d}{dx}\\left({a}\\right)=0$$",
"result": "=0"
}
],
"meta": {
"solvingClass": "Derivatives",
"interimType": "Derivatives",
"gptData": "pG0PljGlka7rWtIVHz2xymbOTBTIQkBEGSNjyYYsjjDErT97kX84sZPuiUzCW6s79Kg+idP5vLVrjUll6eMdYmqQX14xoif/Hxcm4iYenIFJ8Vk6wvKjVnTtwWT18bQnz7FeFrf3rcM8IZlDz2c0dm5O2bEw0Ql6ne7k1AUriTsKfyXa6Zj1lcQsTYejuhcz"
}
},
{
"type": "interim",
"title": "$$\\frac{dx}{dx}=1$$",
"input": "\\frac{dx}{dx}",
"steps": [
{
"type": "step",
"primary": "Apply the common derivative: $$\\frac{dx}{dx}=1$$",
"result": "=1"
}
],
"meta": {
"solvingClass": "Derivatives",
"interimType": "Derivatives",
"gptData": "pG0PljGlka7rWtIVHz2xymbOTBTIQkBEGSNjyYYsjjDErT97kX84sZPuiUzCW6s79Kg+idP5vLVrjUll6eMdYko/29fz701XcRtz4b42RqRjqLYrB3CcI0Y7zGHBJCja+8ZDu8iF4MSewt4yms1lIdz2XHFZ6BxfaHSMA6lT+lbVmoiKRd+ttkZ9NIrGodT+"
}
},
{
"type": "step",
"result": "=0-1"
},
{
"type": "step",
"primary": "Simplify",
"result": "=-1",
"meta": {
"solvingClass": "Solver"
}
}
],
"meta": {
"solvingClass": "Derivatives",
"interimType": "Derivatives"
}
},
{
"type": "step",
"result": "=-\\frac{1}{1-x}\\left(-1\\right)"
},
{
"type": "step",
"primary": "Simplify",
"result": "=\\frac{1}{1-x}",
"meta": {
"solvingClass": "Solver"
}
}
],
"meta": {
"solvingClass": "Derivatives",
"practiceLink": "/practice/derivatives-practice#area=main&subtopic=Chain%20Rule",
"practiceTopic": "Chain Rule"
}
},
"plot_output": {
"meta": {
"plotInfo": {
"variable": "x",
"plotRequest": "y=\\frac{1}{1-x}"
},
"showViewLarger": true
}
},
"meta": {
"showVerify": true
}
}
Solution
Solution
Solution steps
Simplify
Take the constant out:
Apply the chain rule:
Simplify
Graph
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Frequently Asked Questions (FAQ)
What is the derivative of ln(1/(1-x)) ?
The derivative of ln(1/(1-x)) is 1/(1-x)What is the first derivative of ln(1/(1-x)) ?
The first derivative of ln(1/(1-x)) is 1/(1-x)